Question

2.00 * 10^3 g of dinitrogen is mixed with 1.00 *10% g of dihydrogen to produce ammonia according to
the following chemical equation:
N2(g) + 3H2(g) 2NH3(g)
Identify the limiting reagent in the production of NH; in this situation,
Calculate the mass of ammonia produced

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Answer 1

Answer:

Hi Army,,,

Explanation:

here , we observed that,

28 g of N2 reacts with 6g of H2 .

∴ 1g of N2 reacts with 6/28 g of H2

∴ 2000g of N2 will react with 2000× 6/28 = 428.57 of H2

but H2 is given 1 × 10³g > 428.57 g

e.g., H2 is excess available .

hence, N2 is the limiting reagent. it means N2 limits the production of amount of anomia .

28g of N2 produces 34 g of NH3

1g of N2 produces 34/28 g of NH3

2000g of N2 will be produce 34/28 × 2000 = 2428.57 g of NH3 .

                                             Hope it helps u!!!!