√2-1/√2+1=a+b√2 answer fast
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Solution:
LHS =(√2-1)/(√2+1)
Rationalising the denominator, we get
= [(√2-1)(√2-1)]/[(√2+1)(√2-1)]
= (√2-1)²/[(√2)²-1²]
= [(√2)²+1²-2*√2*1]/(2-1)
= 2+1-2√2
= 3-2√3
= 3+(-2)√3
= a+b√2 [ given RHS ]
Compare it , we get.
a = 3 , b = -2
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