Question

(2^-1 ×4^-1)÷2^-2
زرا
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Answer 1

Hi There!

(2^-1 × 4^-1)/(2)^-2

= (1/2 × 1/4)/(1/2)^2

= (1/8)/(1/4)

= 1/8 × 4

= 1/2

= 2^-1

Answer 2

Answer:

$( {2}^{ - 1} \times {4}^{ - 1} ) \div {2}^{ - 2} \\ = \frac{ \frac{1}{2} \times \frac{1}{4} }{ \frac{1}{ {2}^{2} } } \\ = \frac{ \frac{1}{2} \times \frac{1}{4} }{ \frac{1}{4} } \\ = \frac{1}{2} \times \frac{1}{4} \times 4 \\ = \frac{1}{2} \\ = {2}^{-1}$

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