(2^-1/5^-1)^2*(-5/8)^-1
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Answered by
59
Exponents,
Given that,
(2-²/5-¹)^2×(-5/8)-¹
={(1/2)/(1/5)}² × 8/-5
= (5/2)² × -8/5
= 25/4 × -8/5
= 5 × (-2)
= -10
Do you know who invented exponents ?
You might know or not
but let me tell
A French Mathematician named Edvard Larouge, created the Exponent in 1863.
He had to multiply the numbers again and again ,because he was a banker and got this idea.
That's it
Hope it helped (･ิω･ิ)
Given that,
(2-²/5-¹)^2×(-5/8)-¹
={(1/2)/(1/5)}² × 8/-5
= (5/2)² × -8/5
= 25/4 × -8/5
= 5 × (-2)
= -10
Do you know who invented exponents ?
You might know or not
but let me tell
A French Mathematician named Edvard Larouge, created the Exponent in 1863.
He had to multiply the numbers again and again ,because he was a banker and got this idea.
That's it
Hope it helped (･ิω･ิ)
Answered by
19
Hey friend
Here’s your answer
(2-²/5-¹)^2×(-5/8)-¹
={(1/2)/(1/5)}² × 8/-5
= (5/2)² × -8/5
= 25/4 × -8/5
= 5 × (-2)
= -10
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