Question

2.11. A cylindrical conductor of length 1 and uniform
area of cross-section A has resistance R. Another
conductor of length 21 and resistance R of the
same material has area of cross-section:

(a) A/2
(6) 3A/2
(d) 3A
(C) 2A​

Answer 1

Answer:

The resistance is given R so that the area depends on the length that is 2L; hence the area will also become double. Thus, the uniform area of cross-section of another cylindrical conductor will be 2A .

Explanation:

c) 2a

hope it is useful..

Answer 2

Answer:

c) 2A

Explanation:

Resistance of a conductor with length(l) and cross section area(A) is given by

$R = \rho \frac{l}{A}..........(1)$

Also, fow the second wire

$R = \rho \frac{2l}{A₂}...........(2)$

From (1) and (2), we get

$\rho \frac{l}{A} = \rho \frac{2l}{A₂}$

$\frac{1}{A} = \frac{2}{A₂}$

$A₂= 2A$