Math, asked by guptarahul56, 1 year ago

[(2/13)^-6÷(2/13)^3]^3×(2/13)^-9

Answers

Answered by madhura41
11
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Here is u r Ans ➡


 = (( \frac{2}{13}  {}^{ - 6}  \div ( \frac{2}{1 3} ) {}^{3} ) {}^{3}  \times ( \frac{2}{13} ) {}^{ - 9}

 = using \:  >  \: ( \frac{a}{b} ) {}^{ - n}  = ( \frac{b}{a} ) {}^{n}

 = (( \frac{23}{2} ) {}^{6} ) \div  \frac{8}{2197} ) {}^{3}  \times ( \frac{13}{2}) {}^{9}

 = ( \frac{23 {}^{6} }{2 {}^{6} } \times  \frac{2197}{8} ) {}^{3}  \times  \frac{13 {}^{9} }{2 {}^{9} }

 =  \frac{23 {}^{18} }{2 {}^{18} }  \times ( \frac{2197}{8} ) {}^{3}  \times  \frac{13 {}^{9} }{2 {}^{9} }

 =  \frac{23 {}^{18} }{2 {}^{18}  }  \times  \frac{2197 {}^{3} }{8 {}^{3} }  \times  \frac{13 {}^{9} }{2 {}^{9} }

 =  \frac{23 {}^{18}  \times 2197 {}^{3}  \times 13 {}^{9} }{2 {}^{27}  \times 8 {}^{3} }
 =  \frac{23 {}^{18}  \times 13 {}^{9}  \times 13 {}^{9} }{2 {}^{27} \times 2 {}^{9}  }

 =  \frac{299 {}^{18} }{2 {}^{36} }

 = in \: decimal \: form \:  >  \: 5.30886 \times 10 {}^{33}
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