Question

(ії) р² + бр – 16. please solve it by using factorization algebraic identities identity is (x+a)(x+b)​

Answer 1

Answer:

(p - 2) (p + 8)

Step-by-step explanation:

p^2 +6p -16

p^2 +8p -2p -16

p(p + 8). -2(p + 8)

(p - 2) (p + 8)

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Answer 2

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Step-by-step explanation:

So we have p^2+6p-16

so out of numerous ways to approach it one way is that we have to find the factors of 16 and check whether it sums upto 6 or not

so we see that 8×-2=16 and 8+(-2)=6

hence, by splitting the middle term we get

p^2+6p-16=p^2+8p -2p-16

=p(p+8)-2(p+8)

on taking (p+8) common we get

(p+8)(p-2)

so we have x=p

a=8

b=-2

*note that b is not 2 but -2

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