Math, asked by shubhadasachinjadhav, 18 days ago

2.1fx (3+√8); find the value of (x²+1/x²)​

Answers

Answered by manicheeda48
0

Answer:

x+x1=3−22+3−221

x1=3−221×3+223+22

 =13+22

x+x1

=3−22+3+22

 

=6

Squaring on both sides, 

(x+x1)2=36

x2+x21=36−2

⇒x2+x21

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