Yao throws a die twenty times and records his observation as represented 4,2,1,6,5,3,5,6,1,2,1,5,5,6,3,4,3,5,1,5 construct a frequency distribution table and find the mode,median,and mean of yao's observation
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Mean=
number of observations
sum of observations
⇒ Mean=
15
1+1+1+2+2+2+3+3+4+4+5+5+6+6
=
15
47
=3.13
Now, total number of observations =15, which is odd.
∴ Median =8
th
term =3
Now, the observation 2 occurs the most i.e., 4 times
∴ Mode =2
Hence, Mean =3.13, Median =3 and Mode=2$$.
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