Math, asked by SouritraPharikal, 2 months ago

[{⅓)^2}^-2]^-1

(a)¹/81 (b) ¹/9 (c)-¹/81 (d) -¹/9

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Answered by tejeswarteju

2

Answer:

$\frac{1}{81} \: \: \: \: \: \:$

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