(2) 2.16g of copper metal when treated with nitric acid followed by ignition of the nitrate
gave 2.7 g of Cuo. In another experiment 1.15g of copper oxide upon reduction with
hydrogen gave 0.92 g of copper. Show that the above data illustrates the law of definite
proportion.
Answers
Answer:
Explanation:
Experiment A: 2.16g of copper metal when treated with nitric acid followed by ignition of the nitrate gave 2.7 g of Cuo.
=> For the given process, we can write the chemical reaction as:
Cu + 4HNO₃→Cu(NO₃)₂ + 2NO₂ + H₂O
2Cu(NO₃)₂ → 2CuO + 2NO₂ + O₂
=> Here, one mole of copper metal will form one mole of copper oxide as the end product.
atomic weight of Copper = 63g (reactant)
molecular weight of copper oxide = 79g (product)
∴ CuO/Cu = 79/63 = 1.25
CuO/Cu as per the detail given for Experiment A = 2.7/2.16 = 1.25
Experiment B: 1.15g of copper oxide upon reduction with hydrogen gave 0.92 g of copper.
=> Chemical reaction for this process:
CuO+H₂→ Cu + H₂
=> In this reaction, Reactant is Copper oxide ( 63g) and product is Copper metal ( 79g)
∴ CuO/Cu = 79/63 = 1.25
According to experimental data, Cuo/Cu = 1.25
So, in both the case, ratio Cuo/Cu is remain same (1.25) which proves the the law of definite proportion.
Experiment A: 2.16g of copper metal when treated with nitric acid followed by ignition of the nitrate gave 2.7 g of Cuo.
=> For the given process, we can write the chemical reaction as:
Cu + 4HNO₃→Cu(NO₃)₂ + 2NO₂ + H₂O
2Cu(NO₃)₂ → 2CuO + 2NO₂ + O₂
=> Here, one mole of copper metal will form one mole of copper oxide as the end product.
atomic weight of Copper = 63g (reactant)
molecular weight of copper oxide = 79g (product)
∴ CuO/Cu = 79/63 = 1.25
CuO/Cu as per the detail given for Experiment A = 2.7/2.16 = 1.25
Experiment B: 1.15g of copper oxide upon reduction with hydrogen gave 0.92 g of copper.
=> Chemical reaction for this process:
CuO+H₂→ Cu + H₂
=> In this reaction, Reactant is Copper oxide ( 63g) and product is Copper metal ( 79g)
∴ CuO/Cu = 79/63 = 1.25
According to experimental data, Cuo/Cu = 1.25
So, in both the case, ratio Cuo/Cu is remain same (1.25) which proves the the law of definite proportion.