2-[2 π{2-(2-1)}]. Can you tell plz
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Answered by
3
It's simple using BODMAS rule. 2-[2π{2-(1)}] = 2-[2π{1}] = 2-2π = 2-2 x 22/7 = 2- 44/7 = 14-44/7 = -30/7. If you want to get more help in physics(Quantum mechanics) You can check my YouTube channel https://youtu.be/MEol99ohgWk
Answered by
2
such type of questions can b solved by following d BODMAS rule:
B: bracket
O:of(same as multiply)
D:division
M:multiplication
A:addition
S:subtraction
2-[2π-{2-1}]
2-[2 π-1]
2-[2*3.14-1]
2-[6.28-1]
2-[6.27]
-4.27 (as 6.27 is greater than b...therefore while subtracting d ans will be in negative form)
B: bracket
O:of(same as multiply)
D:division
M:multiplication
A:addition
S:subtraction
2-[2π-{2-1}]
2-[2 π-1]
2-[2*3.14-1]
2-[6.28-1]
2-[6.27]
-4.27 (as 6.27 is greater than b...therefore while subtracting d ans will be in negative form)
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