Question

(2+2+2+2+2+2+2+2+2 )(3)(3)(3)³³³(452)³²¹=every answers it​

Answer 1

Step-by-step explanation:

Given:-

(2+2+2+2+2+2+2+2+2 )(3)(3)(3)^333×(452)^321

To find:-

Find the value of the given problem?

Solution:-

Given that

(2+2+2+2+2+2+2+2+2 )×(3)(3)(3)^333×(452)^321

=>18×(3)(3)(3)^333×(452)^321

=>2×9×3×3×3^333×(452)^321

=>2×3×3×3×3×3^333×(2×2×113)^321

=>2×3^4×3^333×(2^2×113)^321

=>2×3^4×(2^2)^321×3^333×(113)^321

=>2×3^43^333××2^(2×321)×(113)^321

=>2×3^4×3^333×2^642×(113)^321

=>(2×2^642)×(3^4×3^333)×(113)^321

=>2^(1+642)×3^(4+333)×(113)^321

=>2^643×3^337×(113)^321

Answer:-

answer for the given problem is 2^643×3^337×(113)^321

Used formulae:-

• a^m × a^n = a^(m+n)
• (a^m)^n = a^mn