Question

2×^2-2√6x+3=0 value of x​

Answer 1

Answer:

x 9

Step-by-step explanation:

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Answer 2

Answer:

2x^2 root6x+3=0

2x^2-6x+3=0

(b=b^2-4ac

(-6)^2-4ac

(-6)^2-4 (2)(3)

=36-24

=12 >0=>2 root3>0

real roots

x= -6#rootD/2a

(-6)+2 root3/4

6+2 root3/4=>2 (3+root3)/4

x=3+ root 3

x= 3+ root 2/2 and 3- root 3/2 are the root