Question

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2. Prove that the product of two consecutive positive integers is divisible by 2.
3. Prove that the product of three consecutive positive integer is divisible by 6.​

Answer 1

Answer:

2) Let three consecutive positive integers be, n, n + 1 and n + 2. Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2. ... So, we can say that one of the numbers among n, n + 1 and n + 2 is always divisible by 3. ⇒ n (n + 1) (n + 2) is divisible by 3.

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Answer 2

Answer:

2. product of 2 consecutive +ve integers is divisible by 2

2x3=6 6 can divisible by 2

Step-by-step explanation:

3. the product of 3 consecutive +ve integers is divisible by 6.

three +ve integers =2x3x4=24

24 can divisible by 6.

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