Math, asked by avnitak757, 1 month ago

2√2+√3/3√2+2√3
rationalize the denominator​

Answers

Answered by Dimpi04
0

Step-by-step explanation:

2√2 + √3/3√2 + 2√3

=(2√2 + √3/3√2 + 2√3)×(3√2 - √3)/(3√2 -√3)

={(2√2 + √3)(3√2 - √3)}/(3√2)²-(√3)²

={2√2(3√2 - √3) + √3)(3√2 - √3)}/ 18 - 3

= (12 - 2√6 + 3√6 - 3)/15

= (12 - 3 - 2√6 + 3√6)/15

= (9 +√6)/15

= 9/15 + √6/15

= 3/5 + √6/15

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