Question

√2/ √ 2 +√3 +√ 5 ratiionalise denominator

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\frac{ \sqrt{6} - \sqrt{15} + 3}{12}$

Step-by-step explanation:

$\frac{ \sqrt{2} }{ \sqrt{2} + \sqrt{3} + \sqrt{5} } \\ \\ \frac{ \sqrt{2} [( \sqrt{2} + \sqrt{3} ) - \sqrt{5} ] \: }{[( \sqrt{2 }+ \sqrt{3} ) + \sqrt{5} ) ][( \sqrt{2} + \sqrt{3}) - \sqrt{5} ) ]} \\ \\ \frac{2 + \sqrt{3.2} - \sqrt{2.5} }{ {( \sqrt{2 } + \sqrt{3}) }^{2} -( \sqrt{5} ) ^{2} } \\ \\ \frac{2 + \sqrt{6} - \sqrt{10} }{ {( \sqrt{2} })^{2} + {( \sqrt{3}) }^{2} + 2. \sqrt{2} . \sqrt{3} - 5} \\ \\ \frac{2 + \sqrt{6} - \sqrt{10} }{2 + 3 + 2 \sqrt{6} - 5 } \\ \\ \frac{(2 + \sqrt{6} - \sqrt{10} )}{2 \sqrt{6} } \\ \\ \frac{(2 + \sqrt{6} - \sqrt{10} ) \sqrt{6} }{2 \sqrt{6} \times \sqrt{6} } \\ \\ \frac{2 \sqrt{6} + 6 - \sqrt{5.2.3.2} }{2.6} \\ \\ \frac{2 \sqrt{6} - 2 \sqrt{15} + 6 }{12} \\ \\ \frac{2( \sqrt{6} - \sqrt{15} + 3)}{12} \\ \\ \frac{ \sqrt{6} - \sqrt{15} + 3}{12}$