Question

E total number of prime factors of (3x5)12 (2x7)10 (10)25 is

Answer 1

the total no of prime factors are 13

Answer 2

Solution :

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If x = a^p× b^q× c^r ×...

Here a ,b , c , .. are prime numbers.

Now ,

Total number of prime

factors of x= (p+1)(q+1)(r+1)...

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Here ,

(3x5)^12 (2x7)^10 (10)^25

= 3^12×5^12×2^10×7^10×2^25

×5^25

= 2^25 × 3^12 × 5^27×7^10

Therefore ,

Total number of prime

factors = (25+1)(12+1)(27+1)(10+1)

= 26×13×28×11

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