Question

(2-2/3) + (9-11/3)

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Answer 1

Answer:

20/3

Step-by-step explanation:

(2-2/3)+(9-11/3)

(6-2/3) +(27-11/3)

4/3 + 16/3

4+6/3 =20/3

Answer 2

➤ Answer :-

${\tt\longrightarrow \bigg(2 - \dfrac{2}{3} \bigg) + \bigg(9 - \dfrac{11}{3} \bigg)}$

${\tt\longrightarrow \bigg( \dfrac{2}{1} - \dfrac{2}{3} \bigg) + \bigg( \dfrac{9}{1} - \dfrac{11}{3} \bigg)}$

Now, we will solve step by step......

First, we'll should solve the first bracket and then we should solve second bracket.........

${\tt\longrightarrow \bigg( \dfrac{2}{1} - \dfrac{2}{3} \bigg)}$

Convert them into like fractions by taking the LCM of the denominators i.e, 1 and 3........

LCM of 1 and 3 is 3.

${\tt\longrightarrow \dfrac{2 \times 3}{1 \times 3} - \dfrac{2}{3} = \boxed{ \tt\dfrac{6}{3} - \dfrac{2}{3} }}$

${\tt\longrightarrow \dfrac{6 - 2}{3} = \dfrac{4}{3} = \boxed{\tt 1 \dfrac{1}{3}}}$

Now, we should solve second bracket.........

${\tt\longrightarrow \bigg(\dfrac{9}{1} - \dfrac{11}{3} \bigg)}$

Convert them into like fractions by taking the LCM of the denominators i.e, 1 and 3..........

LCM of 1 and 3 is 3.

${\tt\longrightarrow \dfrac{9 \times 3}{1 \times 3} - \dfrac{11}{3} = \boxed{ \tt \dfrac{27}{3} - \dfrac{11}{3}}}$

${\tt\longrightarrow \dfrac{27 - 11}{3} = \dfrac{16}{3} = \boxed{\tt 5 \dfrac{1}{3}}}$

Now, we should add the both answers obtained while we solved first and second bracket...........

${\tt\longrightarrow 1 \dfrac{1}{3} + 5 \dfrac{1}{3}}$

Convert them to improper fractions, so that the calculation becomes easier...........

${\tt\longrightarrow \dfrac{4}{3} + \dfrac{16}{3} = \dfrac{4 + 16}{3}}$

${\tt\longrightarrow \dfrac{20}{3} = 6 \dfrac{2}{3}}$

$\Huge\therefore$The answer is ${\tt 6 \dfrac{2}{3}}$