2.2 cubic dm of brass is to be drawn into a cylindrical wire 0.25 cm in diameter. Find the length of the wire.
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Answered by
36
Answer:
The length of the wire is 448 m .
SOLUTION :
Let the length of the wire be 'h' cm
Given : Volume of metal (brass) = 2.2 dm³ = (2.2 × 10³) cm³ = 2200 cm³
[1 dm³ = 10³ cm]
Volume of metal(brass) = 2200 cm³
Diameter of cylindrical wire , d = 0.25 cm
Radius of the cylindrical wire, r = 0.25/2 = 0.125 cm
Since the metal ( brass) is converted into cylindrical wire, so
Volume of cylindrical wire = Volume of metal (brass) in the wire
πr²h = 2200 cm³
22/7× (0.125)²× h = 2200
0.125 × 0.125 × 22 × h = 2200 × 7
h = (2200 × 7)/ (22 × 0.015625)
h = 15400/0.34375
h = 44800 cm
h = 44800/100
[1 cm = 1/100 m ]
h = 448 m
Hence, the length of the wire is 448 m .
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Answered by
7
Given that 2.2 dm3 of grass is to be drawn into a cylindrical wire 0.25 cm in diameter
Given diameter of cylindrical wire = 0.25 cm
Radius of wire (r) = d/2 = 0.25/2 = 0.125 cm
=0.125×10^-2m.
We have to find length of wire
Let, volume of wire h
Volume of cylinder =
pie r^2h
Volume of brass of 2.2 dm3 is equal to volume of cylindrical wire.
10^-2)h=2.2×10^-3
h= 2.2×10^-3×7
So h=448m.
Hope its help you
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