2
2.
Show that
(1)
(ü)
tan 48° tan 16° tan 42° tan 74° = 1
cos36° cos 54° – sin36º sin 54° = 0.
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Answered by
1
Answer:
what is show that .
Step-by-step explanation:
tan 48° tan 16° tan 42° tab 74° =1
Answered by
4
Step-by-step explanation:
1)L.H.S=tan48tan42tan16tan74
=tan48cot(90-42)tan16cot(90-74)
=tan48cot48tan16cot16
=1
=R.H S
2)L.H.S=cos36cos54-sin36sin54
=cos36sin(90-54)-sin36cos(90-54)
=cos36sin36-sin36cos36
=0
=R.H.S
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