2+ 2+ z2–2–2z –2z, if =−3, =2, =−2
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Correct option is A)
Given :- z2−2z+4=0
z2+4=2x
Problem : ∑n=124(2nzn+zn2n)2
∑n=124((2z)nz2n+22n)2
We know (z2(1)+22(2))=2z(1)
(z2+22)=(2z)2
z4+24+2.z222=(2z)2
z4+24=24z2−8z2
8z
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Solution

Verified by Toppr
Correct option is A)
Given :- z2−2z+4=0
z2+4=2x
Problem : ∑n=124(2nzn+zn2n)2
∑n=124((2z)nz2n+22n)2
We know (z2(1)+22(2))=2z(1)
(z2+22)=(2z)2
z4+24+2.z222=(2z)2
z4+24=24z2−8z2
8z
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