2×(22/7)×0.7×h = 4.4
Or h = 1 how did we get height =1m
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Let h be the height of the circular cylinder and r be the radius. Radius of the base of cylinder, r = 0.7m CSA of cylinder = 2πrh CSA of cylinder = 4.4m2 Equating both the equations, we have 2×(22/7)×0.7×h = 4.4 Or h = 1 Therefore, the height of the cylinder is 1 m.
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