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29. The 4th term of an AP is 11. The sum of the 5th and 7th terms of this AP
is 34. Find its common difference.
[CBSE 2015]
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Explanation:
T
4
=11
T
5
+T
7
=34
a+3d=11,
a+4d+a+6d=34
2a+10d=34
a+5d=17
⇒(a+5d)−(a+3d)=17−11
⇒2d=6
⇒d=3.
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