Question

√2,-✓2are zeros of polynomial then find quadratic eqation

Answer 1

Answer:

x² - 2

Step-by-step explanation:

General Form of a Quadratic Equation: ax² - bx + c

Another form of expressing Quadratic Equation is: x² - sx + p

Here, 's' refers to the sum of the roots or zeros of the equation and 'p' refers to the product of given roots or zeros of the equation.

According to the question,

Zeros = √2 and -√2

⇒ Sum of zeros ( s ) = √2 + ( -√2 )

⇒ Sum of zeros ( s ) = √2 - √2 = 0

⇒ Product of zeros ( p ) = √2 × -√2

⇒ Product of zeros ( p ) = - ( √2 ) × √2 = -2

Hence applying in the equation form, we get,

⇒ x² - sx + p = x² - 0x + ( -2 )

⇒ Equation = x² - 2

This is the required answer.

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