Question

2) 2men and 7 children complete a certain piece of
work in 4 days and 4 men and 4 children complete
the same in only 3 days. Find the number of days
Required to complete the same work by 1 man or
1 child.​

Answer 1

Answer:

Let work done by 1 man in 1 day = x

Let work done by 1 child in 1 day = y

Given,

2x+7y=

4

1...(i) and

4x+4y=

3

1 ....(ii)

Multiplying equation (i) by 2, we get

2x+7y=

4

1

⇒4x+14y=

2

1

....(iii)

Subtracting equation (ii) by (iii), we get

4x+14y=

2

1

4x+4y=

3

1

10y=

2

1

−

3

1

⇒10y=

6

3−2

⇒10y=

6

1

⇒y=

60

1

Putting the value of y in equation (i), we get

2x+7y=

4

1

⇒2x+7(

60

1

)=

4

1

⇒2x=

4

1

−

60

7

⇒2x=

60

15−7

⇒2x=

60

8

⇒2x=

15

2

⇒x=

15

1

∴ Work done by 1 man in 1 day

15

1

.

∴ days taken to complete the job is 15

Step-by-step explanation:

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Answer 2

Answer:

I think it is correct

Don't know