Question

2^2x+1=128.......x=?​

Answer 1

$2^{2x} =127$

Taking log on both sides.

$2xlog2=log127$

$x=\frac{log127}{log4}$

Answer 2

Answer:

2^7=128

2^2x+1= 2^7

equating the powers

2x+1= 7

2x= 6

x= 6/2=3