Question

2^2x+1=4^2x-1; solve for x


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Answer 1

•||Solution||•

$→\; {2}^{(2x+1)} = {4}^{(2x-1)}$

$→\; {2}^{(2x+1)} = {[{2}]^2}^{(2x)}$

$→\; {2}^{(2x+1)} = 2^{(4x-2)}$

$\bf{as \: the \: bases \: are \: equal \: we \: can \: equate \: the \: powers}$

$→\; 2x+1 = 4x-2$

$→\; 2x-4x = -2-1$

$→\; -2x = -3$

$→\; \bold{x = \frac{2}{3}}$

• Value of x ☞ $\Large{\red{\bold{\frac{2}{3}}}}$

$\boxed{\tt{@MrMonarque}}$

Hope It Helps You ✌️

Answer 2

Answer:

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