Question

A bag Rs.1,Rs.2 and Rs.5 coins.if the coins are are in the ratio 1:2:5 and the total money in the bag is Rs.1590 then find the no.of each type of coin.​

Answer 1

Answer:

1 rupee - 5×x = 5x

2 rupee9×2x= 18x

5 rupees4x× 5= 20x

43x= 129

x= 129/43= 3

5× 3 =15

9×3= 27

4×3=12

Answer 2

Answer:

Number of $Rs.1$ coins = $53$

Number of $Rs.2$ coins = $106$

Number of $Rs.5$ coins = $263$

Step-by-step explanation:

It is given that the ratio of the $Rs.1$, $Rs.2$ and $Rs.5$ coins in the bag is $1:2:5$

Let the common multiple of the ratio be $x$

⇒ Number of $Rs.1$ coins = $x$

⇒ Number of $Rs.2$ coins = $2x$

⇒ Number of $Rs.5$ coins = $5x$

Total money in the bag = $Rs.1590$

⇒ $1(x) + 2(2x) + 5(5x) = 1590$

⇒ $x + 4x + 25x = 1590$

⇒ $30x = 1590$

⇒ $x = 53$

∴ Number of $Rs.1$ coins = $x = 53$

  Number of $Rs.2$ coins = $2x = 2(53) = 106$

  Number of $Rs.5$ coins = $5x = 5(53) = 263$