Question

2^2x - 12(2^x) + 32 = 0 solve for x

Answer 1

Answer:

${2}^{2x} - 12 ({2}^{2x} ) + 32 = 0$

${2}^{2x} - {24}^{2x} + 32 = 0$

${ - 22}^{2x} = - 32$

${22}^{2x} = 32$

here is your answer

hope it helps you..!!!

Answer 2

Answer:

{2}^{2x} - 12 ({2}^{2x} ) + 32 = 02

2x

−12(2

2x

)+32=0

{2}^{2x} - {24}^{2x} + 32 = 02

2x

−24

2x

+32=0

{ - 22}^{2x} = - 32−22

2x

=−32

{22}^{2x} = 3222

2x

=32

here is your answer