2+2x-3/2x+3=3x+4/x+2
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Answer:
You have not applied brackets, hence I am taking this question as:
step by step explanation:
2+(2x-3)/(2x+3) = (3x+4)/(x+2)
=> 2 = (3x+4)/(x+2) - (2x-3)/(2x+3)
=> 2 = [6x²+17x+12-(2x²+x-6)]/(2x²+7x+6)
=> 2*(2x²+7x+6) = 4x²+16x+18
=> 4x²+14x+12 = 4x²+16x+18
=> 2x+6 = 0 => x = -3.
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