find the value of sin x + cos x / sin x - cos x if tan x = 3/4
Answers
Step-by-step explanation:
make me brilliant.. i am a +1 student
Given : tan x = 3/4
To Find : value of (sinx + cosx)/(sinx - cosx)
Solution:
sinx/cosx = tanx
(sinx + cosx)/(sinx - cosx)
Divide numerator and denominator by cosx
= (sinx/cos + cosx/cos)/(sinx/cosx - cosx/cosx)
= (tanx + 1)/(tanx - 1)
Substitute tanx = 3/4
= (3/4 + 1)/(3/4 - 1)
multiplying numerator and denominator by 4
= ( 3 + 4)/(3 - 4)
= 7/(-1)
= -7
value of (sinx + cosx)/(sinx - cosx) = -7
Learn More:
Prove that sinα + sinβ + sinγ − sin(α + β+ γ) = 4sin(α+β/2)sin(β+γ
brainly.in/question/10480120
Ifsin 990° sin 780° sin 390°+=K(tan 405° – tan 360°) then Kicos 540 ...
brainly.in/question/22239477
Maximum value of sin(cos(tanx)) is(1) sint (2)
brainly.in/question/11761816
evaluate cot[90-theta].sin[90-theta] / sin theta+cot 40/tan 50 - [cos ...
brainly.in/question/2769339