Math, asked by aravinds6, 1 year ago

2√2x^3+3√3y^3 answer my question plzzz.......

Answers

Answered by ramvishal048
1

Answer:

         = (\sqrt{2} x +\sqrt{3}y) ( 2x+3y-\sqrt{6}xy)

Step-by-step explanation:

          2\sqrt{2}x^{3\\+3\sqrt{3}y^{3}  = (\sqrt{2}x)^{3}+(\sqrt{3} y)^{3}

                                  = (\sqrt{2} x +\sqrt{3}y) ( 2x+3y-\sqrt{6}xy).

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