(2) (2x3 – 7x2 – 5x – 4) = (2x - 1) quotient and remainder?
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2x + 7x? – 5x 4
=2x3 + x? + 6x2 + 3x 8х — 4
=x2 · (2x + 1) + 3x · (2x + 1) – 4. (2x + 1)
= (2x + 1). (x2 + 3x – 4)
Hence quotient is x2 + 3x - 4 and remainder is 0
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