Question

what is electronic configuration of zn²+ (zn=30)​

Answer 1

Answer:

The atomic number of zinc is 30, that says that all zinc atoms have 30 protons in their nuclei. The electron configuration of a neutral zinc atom is 1s22s22p63s23p63d104s2. The Zn2+ ion has lost two electrons, which leaves it with 30 protons and 28 electrons. The electron configuration of Zn2+ is 1s22s22p63s23p63d10.

★Mark as brainliest answer if it helps you ★

Answer 2

Answer:

$Zn^{+2}: 1s^22s^22p^63s^23p^63d^{10}$

Explanation:

First, we will find electronic configuration of Zn.

$Zn:$ $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10}$

In the electronic configuration, 4s will always come before 3d, but when we remove electrons, first we will remove 4s electrons.

So, $Zn^{+2}: 1s^22s^22p^63s^23p^63d^{10}$

In it, two electrons are removed. So 2 electrons are removed from the 4s orbital.

Hope it helps!