Question

2х +2y = 0
2y+ Зx= 0​

Answer 1

Step-by-step explanation:

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Answer 2

Question -

Find the following pair of equations by substitution method -

2x+2y=0

2y+3x=0

Solution -

Given equations,

2x+2y=0.......1)

And,

$2y + 3x = 0$

$2y = - 3x.........2)$

Putting the value of 2y in equation 1) we will get -

$\implies2x + 2y = 0$

$\implies2x + ( - 3x) = 0$

$\implies2x - 3x = 0$

$\implies - x = 0$

$\implies \: x = 0$

Now, substituting the value of x in equation 2) we will get -

$\implies2y + 3x = 0$

$\implies2y + 3 \times 0 = 0$

$\implies2y + 0 = 0$

$\implies2y = 0$

$\implies \: y = \frac{0}{2}$

$\implies \: y = 0$

Verification -

=>2x+2y=0

Putting the value of x and y,

=>2×0+2×0=0

=>0+0=0

=>0=0

Also,

=>2y+3x=0

Putting the value of x and y,

=>2×0+3×0=0

=>0+0=0

=>0=0

L.H.S = R. H. S

Verified.

Therefore the value of x is 0 and y is 0