Math, asked by iqbalahmed1904, 8 months ago

{(⅓)^-²-(½)^-³}÷(¼)^-²

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Answered by Anonymous
7

 \mathcal {SOLUTION:- }

 \tt \frac{  {( \frac{1}{3}) }^{ - 2}   -   { (\frac{1}{2} )}^{ - 3} }{ { \frac{1}{4} }^{ - 2} }  \\  \\  =   \frac{ {3}^{2} -  {2}^{  3}  }{ {4}^{2} }   \\  \\  =  \frac{9 - 8}{16 }  \\  \\  =  \frac{1}{16} \:is \: answer

Answered by kaur12675
1

Step-by-step explanation:

simple reciprocal due to negative power.

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