Math, asked by ahmedwashi88, 1 year ago

{(2/3)^2}^3*(1/3)^-2*3^-1*1/6

Answers

Answered by parmardevu
1
Hey friend..
Here is your answer..

HOPE that it will help you
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Answered by rajeev378
19
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Here is your answer.
(( \frac{2}{3} ) {}^{2} ) {}^{3}  \times ( \frac{1}{3} ) {}^{ - 2}  \times  {3}^{ - 1}  \times  \frac{1}{6}  \\  \\  = ( \frac{2}{3} ) {}^{2 \times 3}  \times (3) {}^{2}  \times  {3}^{ - 1}  \times  \frac{1}{3 \times 2}  \\  \\  =  \frac{2 {}^{6} }{ {3}^{6} }  \times  {3}^{2}  \times  {3}^{ - 1}  \times  \frac{1}{ {3}^{1} \times  {2}^{1}  }  \\  \\  =  {2}^{6 - 1}  \times 3 {}^{2 - 1 - 1 - 6}  \\  \\  =  {2}^{5}  \times  {3}^{ - 6}  \\  \\  =  \frac{ {2}^{5} }{ {3}^{6} }  \\  \\  =  \frac{32}{729}
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