2[3-2(x+4)]=7(3-x)
find x
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2[3-2(x+4)] = 7(3-x)
2[3-2x+8] = 21-7x
2[11-2x] = 21-7x
22-4x = 21-7x
22-4x+7x = 21
22+3X = 21
3X = 21-22
X = -1/3
2[3-2x+8] = 21-7x
2[11-2x] = 21-7x
22-4x = 21-7x
22-4x+7x = 21
22+3X = 21
3X = 21-22
X = -1/3
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