Math, asked by satyank375, 9 months ago

(-2/3+3/4)+1/-5=(-2/3)+[3/4+(1/-5)]​

Answers

Answered by Anonymous
0

Given: (-2/3+3/4)+1/-5=(-2/3)+[3/4+(1/-5)]

Find - Prove Left Hand Side is equal to Right Hand Side

Solution - According to the BODMAS, brackets will be solved first. Hence, first solving left hand side -

First brackets with respect to signs -

(-2/3+3/4)+1/-5  

= (-8+9 /12) + (1/-5)

= +1/12 - 1/5

= 5 - 12 / 60

= -7 / 60

Left Hand Side   = -7 / 60

Now solving right hand side -

(-2/3) + [3/4 + (1/-5)]​

= -2/3 + ( 3/4 - 1/5)

= -2/3 + (15 - 4 /20)

= -2/3 + 11 / 20

= -40 + 33 / 60

Right Hand Side = -7 / 60

Hence proved, Left Hand Side is equal to Right Hand Side which is -7 / 60

Answered by topwriters
0

(-2/3+3/4)+1/-5 = (-2/3)+[3/4+(1/-5)]​ = -7 / 60

Step-by-step explanation:

Given: (-2/3+3/4)+1/-5=(-2/3)+[3/4+(1/-5)]​

Solution: Hierarchy of operators is parenthesis, multiplication/division, addition/subtraction from left to right.

LHS

First processing within parenthesis items.

(-2/3+3/4)+1/-5  = (-8+9 /12) + (1/-5)

  = +1/12 - 1/5

  = 5 - 12 / 60

LHS   = -7 / 60

RHS

First processing within parenthesis items.

(-2/3) + [3/4 + (1/-5)]​ = -2/3 + ( 3/4 - 1/5)

  = -2/3 + (15 - 4 /20)

 = -2/3 + 11 / 20

 = -40 + 33 / 60

RHS = -7 / 60

We find that LHS = RHS = -7 / 60. Hence proved.

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