Question

(-2/3)^-3 should be divided by what that the quotient may be (4/27)^-2.​

Answer 1

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CORRECT QUESTION:-

By what number should

$\sf( \frac{ - 2}{3} {)}^{ - 3}$

be divided so that the quotient may be

$\sf( \frac{4}{27} {)}^{ - 2}$

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ANSWER ♡

Let no. be x

$\sf\frac{ ( \frac{ - 2}{3} {)}^{ - 3} }{x} =\sf ( \frac{4}{27} {)}^{ 2}$

$\sf= > \frac{ (\frac{ - 3}{2} {)}^{3} }{x} = ( \frac{27}{4} {)}$

$\sf= > x = \frac{( \frac{ - 3}{2} {)}^{3} }{( \frac{27}{4} {)}^{2} }$

$\sf\boxed{= > x = \frac{ - 2}{27} }$

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Answer 2

${\bf{\pmb{\color{navy}{Question:-}}}}$

By what number should $\bf( \frac{ - 2}{3} {)}^{ - 3}$ be divided so that the quotient may be $\sf( \frac{4}{27} {)}^{ - 2}$

${\bf{\pmb{\color{navy}{Explanation:-}}}}$

Let no. be x

$\bf\frac{ ( \frac{ - 2}{3} {)}^{ - 3} }{x} =\bf ( \frac{4}{27} {)}^{ 2}$

$\bf \longrightarrow \frac{ (\frac{ - 3}{2} {)}^{3} }{x} = ( \frac{27}{4} {)}$

$\bf= > x = \frac{( \frac{ - 3}{2} {)}^{3} }{( \frac{27}{4} {)}^{2} }$

$\bf\boxed{= > x = \bf\frac{ - 2}{27} }$

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