Question

(2/3)^3 x(2/3)^5 =(2/3)^n-2 then what is n​

Answer 1

Step-by-step explanation:

Given:-

(2/3)^3 x(2/3)^5 =(2/3)^n-2

To find:-

Find the value of n ?

Solution:-

Given equation is :(2/3)^3 x(2/3)^5 =(2/3)^n-2

We know that

a^m × a^n = a^(m+n)

Where , a = 2/3 ; m = 3 and n = 5

=> (2/3)^(3+5) = (2/3)^(n-2)

=> (2/3)^8 = (2/3)^(n-2)

If bases are equal then exponents must be equal.

=> 8 = n -2

=> n -2 = 8

=> n = 8+2

=> n = 10

Answer:-

The value of n for the given problem is 10

Check:-

If n = 10 then

(2/3)^3 x(2/3)^5 =(2/3)^n-2

(2/3)^8 =(2/3)^(10-2)

(2/3)^8 = (2/3)^8

LHS = RHS is true for n = 10

Used formulae:-

• a^m × a^n = a^(m+n)

• If bases are equal then exponents must be equal.

Answer 2

Answer:

here is your answer in the attachment

hope it helps mark as brainliest please