Question

2+3+4+....+15 கூடுதல்​

Answer 1

Answer:

2+3+4+....+15 = 7 Hope it's helpful to you

Answer 2

Answer:

The sum of the given arithmetic series is 119.

Step-by-step explanation:

Assuming the question is to find the sum of $2+3+4+....+15$

The given consecutive terms are in arithmetic series:  

$2+3+4+....+15$

Arithmetic series is a sequence of terms, where the difference between any two terms is a constant.

The sum of n terms in arithmetic sequence is given by

$S_n=\dfrac{n}{2} \big(2a+(n-1)\times d\big)$

where $a$ is the first term and d is the common difference

If first and last term are given, then the sum of n terms is

$S_n=\dfrac{n}{2} \big(a+l\big)$

where $l$ is the last term.

The nth term of arithmetic sequence is given by

$a_n=a+(n-1) d$

In the given the common difference d is 1, the first term is 2 and the last term is 15.  

Substituting these values in the above formula,

$15=2+(n-1) 1\implies 15=1+n\implies n=14$

Thus, the sum of the given numbers is

$S_n=\dfrac{14}{2} \big(2+15\big)=7\times 17=119$

So, the sum of the given arithmetic series is 119.

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