Math, asked by neha4781511, 11 months ago

2+3+5+6+8+9+.....+(3n-1)+(3n)

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Answers

Answered by Anonymous

Answer:

Step-by-step explanation:

$2 + 3 + 5 + 6 + 8 + 9 + ....... + (3n - 1) + (3n)$

$= {2 + 3} + {5 + 6} + {8 + 9} + ....... + {(3n - 1) + (3n)}$

It is an AP with first term a = 5, common difference 6 and last term 6n - 1

Sum = $\frac{n}{2} (a+l) = \frac{n}{2} (5+6n-1) = \frac{n}{2} (4+6n) =n(2+3n)=n(3n+2)$

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