Question

2/√3-√5 rationalise the dinominator​

Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

2/√3-√5

Rationalising factor of √3-√5 is √3+√5

= 2/√3-√5 * √3+√5/√3+√5 ( multiply √3+√5 for both numerator and denominator

=2(√3+√5) / (√3)^2-(√5)^2 ( since (√3+√5)(√3-√5) is in the form of (a+b)(a-b) =a^2-b^2

=2(√3+√5) / 3-5

=2(√3+√5) / -2

= here 2 and -2 gets cancelled so,we get

=(√3+√5)/-1 as there shd not b minus in denominator . so take minus to numerator

= -(√3+√5)/1

= -(√3+√5)

= -√5 -√3