Question

2
3. A wire is bent in the shape of a rectangle of sides
20 cm and 16 cm. If it is bent in the shape of a
square, then what will be the length of the square?​

Answer 1

Answer:

$\huge{\fcolorbox{lime}{black}{\pink{Answer}}}\:$

18cm

Step-by-step explanation:

Question⤵️

A wire is bent in the shape of a rectangle of sides 20 cm and 16 cm. If it is bent in the shape of a square, then what will be the length of the square?

Answer⤵️

$\underline{\green{\sf Given:- }}$

Sides of Rectangle: 20cm and 16cm

$\underline{\orange{\sf To\:Find}}$

Length of the square if the rectangle is bent in the shape of a square.

$\underline{\purple{\sf Formula}}$

1. Perimeter of rectangle: 2(l+b)
2. Perimeter of square: 4$\times$Side

$\underline{\red{\sf Solution}}$

Perimeter of rectangle = 2(l+b)

• 2(20+16)
• 2(36)
• 72

Therefore, perimeter of rectangle is 72cm.

As the shape is remoulded, the perimeter of both Rectangle and Square would be the same.

Therefore, Perimeter of the square is also 72cm.

$\underline{\blue{\sf Assume}}$

Let the side of the square be x.

Perimeter of the square

• Side$\times$4
• 4x=72
• x= $\displaystyle\frac{\cancel{72}}{\cancel{4}}$
• x=18

Hence, the side of the square is 18cm.

Answer 2

Step-by-step explanation:

Side× 4

4x=72

x= 4/72

x=18

Hence, the side of the square is 18cm.