Math, asked by nsuneel, 1 year ago

2/3 a2b2c2 + 4/3ab2c2 / 1/2abc

Answers

Answered by mysticd
4
Solution :

(2/3) a²b²c² +[ (4/3)ab²c²/(1/2)abc ]

= (2/3)a²b²c² + (8/3)bc

= (2/3) bc [ a²bc + 4 ]

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