2/3 a2b2c2 + 4/3ab2c2 / 1/2abc
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Solution :
(2/3) a²b²c² +[ (4/3)ab²c²/(1/2)abc ]
= (2/3)a²b²c² + (8/3)bc
= (2/3) bc [ a²bc + 4 ]
••••
(2/3) a²b²c² +[ (4/3)ab²c²/(1/2)abc ]
= (2/3)a²b²c² + (8/3)bc
= (2/3) bc [ a²bc + 4 ]
••••
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