Question

θ=2π/3 then prove that secθ + sec2θ + sec4θ = -4 ​

Answer 1

Answer:

Let, y = secA+sec2A +sec4A

or, y = sec(2π/3)+sec(4π/3)+sec(8π/3)

or, y = sec(π-π/3)+sec(π+π/3)+sec(5×π/2+π/6)

or, y = -sec(π/3)-sec(π/3)-cosec(π/6)

or, y = -2-2-2 = -6

Answer 2

Answer:

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