Question

(2/3)^x+1÷ (2/3)^-2= (2/3)^6​

Answer 1

Answer:

$\huge\boxed{x=3}$

Step-by-step explanation:

$\left(\dfrac{2}{3}\right)^{x+1}\div\left(\dfrac{2}{3}\right)^{-2}=\left(\dfrac{2}{3}\right)^3\qquad|\text{use}\ a^n\div a^m=a^{n-m}\\\\\left(\dfrac{2}{3}\right)^{x+1-(-2)}=\left(\dfrac{2}{3}\right)^6\iff x+1+2=6\\\\x+3=6\qquad|\text{subtract 3 from both sides}\\\\x=3$