Math, asked by jothijoe0236, 9 months ago

2^30+2^29+2^28/2^31+2^30-2^29=7/10​

Answers

Answered by annantosebas69
4

2³⁰ + 2²⁹ + 2²⁸/2³¹ + 2³⁰ - 2²⁹.

Solution:-

(2³⁰ + 2²⁹ + 2²⁸)/(2³¹ + 2³⁰ - 2²⁹)

= 2²⁸(2³⁰/2²⁸ + 2²⁹/2²⁸ + 2²⁸/2²⁸)/2²⁹(2³¹/2²⁹ + 2³⁰/2²⁹ - 2²⁹/2²⁹)

= 2²⁸(2² + 2 + 1)/2²⁹(2² + 2 - 1)

= (4 + 2 +1)/2²⁹⁻²⁸(4 + 2 -1)

7/2(5)

= 7/10 = RHS

hope it helps, plz mark as brainliest answer

Answered by meenamalik803
1

Taking 2^28 as common from both numerator and denominator,

2^28(2^2+2^1+1)/2^28(2^3+2^2+2^1)

=2^2+2^1+1/2^3+2^2+2^1

=4+2+1/8+4-2

=7/10

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